2)已知有如下不确定推理规则:r1:C11∨C12TH10.7;r2:H1TH0.5;r3:C21∧C22TH-0.6;r4:(C31∧C32)∨C33TH0.8;CF(C11)=0.8,CF(C12
根据MYCIN的确定性方法,我们需要先计算每个规则的CF值,然后根据规则的置信度和前提条件的CF值计算出结论的CF值。
首先计算每个规则的CF值:
CF(r1) = min(CF(C11), CF(C12), T(r1)) = min(0.8, 0.9, 0.7) = 0.7
CF(r2) = CF(H1) = 0.5
CF(r3) = min(CF(C21), CF(C22), T(r3)) = min(0.3, 0.6, -0.6) = -0.6
CF(r4) = min(CF(C31), CF(C32), CF(C33), T(r4)) = min(0.9, 0.5, 0.7, 0.8) = 0.5
然后根据规则的置信度和前提条件的CF值计算出结论的CF值:
CF(H) = (CF(r1) * CF(r2) + CF(r3)) / (1 - min(0, CF(r1) * CF(r2) + CF(r3))) = (0.7 * 0.5 - 0.6) / (1 - min(0, 0.7 * 0.5 - 0.6)) = 0.233
因此,根据给定的不确定推理规则和条件,CF(H)的值为0.233。
首先计算每个规则的CF值:
CF(r1) = min(CF(C11), CF(C12), T(r1)) = min(0.8, 0.9, 0.7) = 0.7
CF(r2) = CF(H1) = 0.5
CF(r3) = min(CF(C21), CF(C22), T(r3)) = min(0.3, 0.6, -0.6) = -0.6
CF(r4) = min(CF(C31), CF(C32), CF(C33), T(r4)) = min(0.9, 0.5, 0.7, 0.8) = 0.5
然后根据规则的置信度和前提条件的CF值计算出结论的CF值:
CF(H) = (CF(r1) * CF(r2) + CF(r3)) / (1 - min(0, CF(r1) * CF(r2) + CF(r3))) = (0.7 * 0.5 - 0.6) / (1 - min(0, 0.7 * 0.5 - 0.6)) = 0.233
因此,根据给定的不确定推理规则和条件,CF(H)的值为0.233。
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